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\title{Operating Systems - assignment 3}
\author{Camil Staps\\\small{s4498062}}

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\section*{5.16}
Suppose two processes $p_1,p_2$ each call \texttt{semWait(s)} when $s=0$. Suppose further that $p_1$ executes until \texttt{semWaitB(delay)}, after which $p_2$ gains control and does the same. Both processes will set \texttt{mutex} to one, and both processes are placed in the delay queue when executing \texttt{semWaitB(delay)}. Unless there are other processes running simultaneously, these processes will never get a signal to stop waiting for \texttt{delay}.

Swapping the lines \texttt{semSignalB(mutex)} and \texttt{semWaitB(delay)} would ensure that this doesn't happen.

\section*{5.18}
The passenger doesn't necessarily get out of the car he gets in to.

For example, passengers $p_1,p_2$ may take cars $c_1,c_2$ respectively. Then suppose $c_2$ finishes driving around. It can happen that $p_1$ then continues walking around, while actually he got in to $c_1$.

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